Considerando as sentenças a seguir:
I. (a + b) 3 − (a − b) 3 = 6a2b + 2b 3
II. (a + b) 2 + (a + b) ∙ (a − b) = 2a 2 + 2ab − b 2
III. 2 ∙ (p + k) 2 − (p − k) 2 = 3p 2 − 2pk − 3k 2
IV. (x + 2) 3 + (x − 2) 3 = 2x 3 + 24x
Considerando as sentenças a seguir:
I. (a + b) 3 − (a − b) 3 = 6a2b + 2b 3
II. (a + b) 2 + (a + b) ∙ (a − b) = 2a 2 + 2ab − b 2
III. 2 ∙ (p + k) 2 − (p − k) 2 = 3p 2 − 2pk − 3k 2
IV. (x + 2) 3 + (x − 2) 3 = 2x 3 + 24x
